Practicing Success
Practicing Success
CUET Preparation Today
The vectors \(2\hat{i}+\hat{j}-\hat{k}\) is perpendicular to \(\hat{i}-4\hat{j}+\lambda \hat{k}\), if \(\lambda\) is equal to |
\(0\) \(-1\) \(-2\) \(-3\) |
\(-2\) |
| \(\begin{aligned}\left(2\hat{i}+\hat{j}-\hat{k}\right)\cdot \left(\hat{i}-4\hat{j}+\lambda \hat{k}\right)&=0\\ 2-4-\lambda&=0\\ \lambda &=-2\end{aligned}\) |
