A battery of 2 V and internal resistance of 0.5 Ω is connected across a resistance of 9.5 Ω. The number of electrons passing through the resistance in 1 second.

$1.25\times 10^{18}$

The correct answer is option (1) : $1.25\times 10^{18}$

$⇒i=\frac{2}{9.5+0.5}⇒i=\frac{2}{10}=\frac{1}{5}A$

$⇒n \times e =\frac{1}{5}⇒n=\frac{1}{5\times 1.6\times 10^{-19}}=1.25\times 10^{18}$