Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Ray Optics

Question:

In Young’s double slits experiment how many maxima can be obtained on the screen if wavelength of light used is 200 nm and distance between slits d = 700 nm

Options:

12

7

18

15

Correct Answer:

7

Explanation:

$\text{Maximum number of fringes are } = \frac{2d}{\lambda} = 2\times \frac{700}{200} = 7$