Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Differential Equations

Question:

$y=a e^{m x}+b e^{-m x}$ satisfies which of the following differential equations?

Options:

$\frac{d y}{d x}-m y=0$

$\frac{d y}{d x}+m y=0$

$\frac{d^2 y}{d x^2}+m^2 y=0$

$\frac{d^2 y}{d x^2}-m^2 y=0$

Correct Answer:

$\frac{d^2 y}{d x^2}-m^2 y=0$

Explanation:

We have, $y=a e^{m x}+b e^{-m x}$

$\Rightarrow \frac{d y}{d x}=m a e^{m x}-m b e^{-m x}$

$\Rightarrow \frac{d^2 y}{d x^2}=m^2\left(a e^{m x}+b e^{-m x}\right)$

$\Rightarrow \frac{d^2 y}{d x^2}=m^2 y \Rightarrow \frac{d^2 y}{d x^2}-m^2 y=0$

Hence, option (d) is correct.