Find a unit vector in the direction of $\vec{PQ}$, where $P$ and $Q$ have coordinates $(5, 0, 8)$ and $(3, 3, 2)$, respectively. |
$\frac{2}{7}\hat{i} - \frac{3}{7}\hat{j} + \frac{6}{7}\hat{k}$ $-\frac{2}{7}\hat{i} + \frac{3}{7}\hat{j} - \frac{6}{7}\hat{k}$ $-2\hat{i} + 3\hat{j} - 6\hat{k}$ $-\frac{2}{49}\hat{i} + \frac{3}{49}\hat{j} - \frac{6}{49}\hat{k}$ |
$-\frac{2}{7}\hat{i} + \frac{3}{7}\hat{j} - \frac{6}{7}\hat{k}$ |
The correct answer is Option (2) → $-\frac{2}{7}\hat{i} + \frac{3}{7}\hat{j} - \frac{6}{7}\hat{k}$ ## Since, the coordinates of $P$ and $Q$ are $(5, 0, 8)$ and $(3, 3, 2)$, respectively. $∴\vec{PQ} = \vec{OQ} - \vec{OP}$ $= (3\hat{i} + 3\hat{j} + 2\hat{k}) - (5\hat{i} + 0\hat{j} + 8\hat{k})$ $= -2\hat{i} + 3\hat{j} - 6\hat{k}$ $∴$ Unit vector in the direction of $\vec{PQ} = \frac{\vec{PQ}}{|\vec{PQ}|}$ $= \frac{-2\hat{i} + 3\hat{j} - 6\hat{k}}{\sqrt{(-2)^2 + (3)^2 + (-6)^2}}$ $= \frac{-2\hat{i} + 3\hat{j} - 6\hat{k}}{\sqrt{49}} = \frac{-2\hat{i} + 3\hat{j} - 6\hat{k}}{7}$ |