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If $\begin{vmatrix}a&b&c\\m&n&p\\x&y&z\end{vmatrix}=k$, then $\begin{vmatrix}6a&2b&2c\\3m&n&p\\3x&y&z\end{vmatrix}=$ |
$\frac{k}{6}$ $2k$ $3k$ $6k$ |
$6k$ |
Taking 3 common from $C_1$ and 2 from $R_1$ $\begin{vmatrix}6a&2b&2c\\3m&n&p\\3x&y&z\end{vmatrix}=3×2\begin{vmatrix}a&b&c\\m&n&p\\x&y&z\end{vmatrix}=6k$ |
