The function $f(x)=\frac{x^2-25}{(x+5)}, x≠-5 $ is :
Answer & explanation
Correct answer: option 3
$f(x)=\frac{x^2-25}{x+5}$
this function is discontinuous at only $x = -5$
which is not in its domain
⇒ f(x) is continuous only
The function $f(x)=\frac{x^2-25}{(x+5)}, x≠-5 $ is :
Correct answer: option 3
$f(x)=\frac{x^2-25}{x+5}$
this function is discontinuous at only $x = -5$
which is not in its domain
⇒ f(x) is continuous only