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The function $f(x)=\frac{x^2-25}{(x+5)}, x≠-5 $ is : |
Discontinuous function Discontinuous function at x= 5 only Continuous function Continuous at x= 5 only |
Continuous function |
$f(x)=\frac{x^2-25}{x+5}$ this function is discontinuous at only $x = -5$ which is not in its domain ⇒ f(x) is continuous only |
