The function $f(x)=\frac{x^2-25}{(x+5)},

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Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Applications of Derivatives

Question:

The function $f(x)=\frac{x^2-25}{(x+5)}, x≠-5 $ is :

Options:

Discontinuous function

Discontinuous function at x= 5 only

Continuous function

Continuous at x= 5 only

Correct Answer:

Continuous function

Explanation:

$f(x)=\frac{x^2-25}{x+5}$

this function is discontinuous at only $x = -5$

which is not in its domain

⇒ f(x) is continuous only