CUET Preparation Today
A flashlight has 8 batteries out of which 3 are dead. If two batteries are selected without replacement and tested, then probability that both are dead is |
$\frac{33}{56}$ $\frac{9}{64}$ $\frac{1}{14}$ $\frac{3}{28}$ |
$\frac{3}{28}$ |
The correct answer is Option (4) → $\frac{3}{28}$ ## Required probability $= P(D) \cdot P(D) = \frac{3}{8} \times \frac{2}{7} = \frac{3}{28}$ |
