Four bad apples are accidently mixed with sixteen good apples. Let X denote the number of bad apples in a random draw of two apples. Then
A. $P(X=0)=\frac{12}{19}$
B. $E(X)=\frac{3}{5}$
C. Standard Deviation of $X=\frac{12}{5\sqrt{19}}$
D. $P(X+2)=\frac{32}{95}$
E. $Var(X)=\frac{144}{475}$
Choose the correct answer from the options given below :
Answer & explanation
Correct answer: option 3
The correct answer is Option (3) → Only A
Ways to Choose 2 good apples,
Ways = ${^{16}C}_2=120$
Ways to Choose any 2 apples,
${^{20}C}_2=190$
$∴P(X=0)=\frac{120}{190}=\frac{12}{19}$ ($X=0$; Both apples are good)