Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Differential Equations

Question:
What is the order and degree of the differential equation $(\frac{ds}{dt})^4+3s\frac{d^2s}{dt^2}=0$?
Options:
order 1 degree 2
order 2 degree 1
order 2 degree 2
order 1 degree1
Correct Answer:
order 2 degree 1
Explanation:
The highest order derivative present in the differential equation is $\frac{d^2s}{dt^2}$. So the order is 2. The given differential equation is a polynomial in $\frac{d^2s}{dt^2}$ and $\frac{ds}{dt}$ where the power of $\frac{d^2s}{dt^2}$ is 1. Hence it is a differential equation of degree 1.