What is the order and degree of the differential equation $(\frac{ds}{dt})^4+3s\frac{d^2s}{dt^2}=0$?
Answer & explanation
Correct answer: option 2
The highest order derivative present in the differential equation is $\frac{d^2s}{dt^2}$. So the order is 2. The given differential equation is a polynomial in $\frac{d^2s}{dt^2}$ and $\frac{ds}{dt}$ where the power of $\frac{d^2s}{dt^2}$ is 1. Hence it is a differential equation of degree 1.