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| What is the order and degree of the differential equation $(\frac{ds}{dt})^4+3s\frac{d^2s}{dt^2}=0$? |
order 1 degree 2 order 2 degree 1 order 2 degree 2 order 1 degree1 |
| order 2 degree 1 |
| The highest order derivative present in the differential equation is $\frac{d^2s}{dt^2}$. So the order is 2. The given differential equation is a polynomial in $\frac{d^2s}{dt^2}$ and $\frac{ds}{dt}$ where the power of $\frac{d^2s}{dt^2}$ is 1. Hence it is a differential equation of degree 1. |
