How many 3 digit even numbers can be formed from the digits (0-9) if repetition of digits are allowed?

450

With number 0 to 9

Most importantly, 3 digits number are formed if 100th place is not zero.

So, for One's place, number of digits that may be used are = 5 (0,2,4,6,8)

Since repetition is allowed, for Ten's place, number of digits that may be used are = 10 (0 to 9)

for Hundred's place, number of digits that may be used are = 9

So the required number of three digit even positive number can be formed from the digits 0 to 9 = 5*10*9

The correct answer is Option (3) → 450