Three resistances of magnitude $2 \Omega, 3 \Omega$ and $5 \Omega$ are connected in parallel to a battery of 10 V and of negligible resistance. The potential difference across $3 \Omega$ resistance will be:

10 V

The correct answer is Option (4) → 10 V

$\frac{1}{R_{eq}}=\frac{1}{2}+\frac{1}{3}+\frac{1}{5}$ [As connected in parallel]

$\frac{1}{R_{eq}}=\frac{15+10+6}{30}=\frac{31}{30}$

Potential difference across 3Ω = 10V

[As each resistance is connected in parallel]

∴ Potential difference around each is equal.