Three resistances of magnitude \( 2\,\Omega,\ 3\,\Omega \) and \( 5\,\Omega \) are connected in parallel to a battery of 10 V and of negligible resistance. The potential difference across \( 3\,\Omega \) resistance will be:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 10 V
In a parallel combination every resistor is connected across the same two points, so all of them have the same potential difference. The battery has negligible internal resistance, so there is no drop inside it and this common potential difference equals the emf.
\( V_{3\,\Omega} = V_{\mathrm{battery}} = 10\,\mathrm{V} \)
The resistance values decide only how the current divides among the branches (5 A, 10/3 A and 2 A); they do not change the potential difference.
Note: The same question was also asked in CUET (UG) 2023 on 02-06-2023 (Slot 2).