Three resistances of magnitude $2 \Omega, 3 \Omega$ and $5 \Omega$ are connected in parallel to a battery of 10 V and of negligible resistance. The potential difference across $3 \Omega$ resistance will be:
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → 10 V
$\frac{1}{R_{eq}}=\frac{1}{2}+\frac{1}{3}+\frac{1}{5}$ [As connected in parallel]
$\frac{1}{R_{eq}}=\frac{15+10+6}{30}=\frac{31}{30}$
Potential difference across 3Ω = 10V
[As each resistance is connected in parallel]
∴ Potential difference around each is equal.