In a circle, chords AB and CD intersect internally, at E. If CD = 16 cm, DE = 6 cm, AE = 12 cm, and BE = X cm then the value of x is: |
6 17 5 9 |
5 |
CD = 16 cm DE = 6 cm CE = 16 - 6 = 10 cm According to the concept, 12 × x = 6 × 10 = x = 5 Therefore, x is 5 cm. |