Target Exam

CUET

Subject

General Test

Chapter

Quantitative Reasoning

Topic

Trigonometry

Question:

If θ = 9°, find the value of cotθ . cot2θ . cot3θ . cot4θ . cot5θ . cot6θ. cot7θ . cot8θ . cot9θ.

Options:

\(\sqrt {3}\) - 1

1

\(\sqrt {3}\)

\(\frac{1}{\sqrt {3}}\)

Correct Answer:

1

Explanation:

Put θ = 9°

⇒ cot9° . cot18° . cot27° . cot36° . cot45° . cot54° . cot63°. cot72° . cot81°

Here, ⇒ (cot A . cot B = 1, when A + B = 90°)

So,

⇒ (cot9° . cot81°) . (cot18° . cot72°) . (cot27° . cot63°) . (cot36° . cot54°) . cot45°

= 1 × 1 × 1 × 1 × 1 = 1