If x + $\frac{1}{x}$= -2, then what is the value of $x^7 +x^{-7} +x^2 +x^{-2} $ ? ( x < 0)
Answer & explanation
Correct answer: option 4
If x + $\frac{1}{x}$= -2
This is only possible only when x = -1
So put the value of x in the given equation,
$x^7 +x^{-7} +x^2 +x^{-2} $ = $1^7 +1^{-7} +1^2 +1^{-2} $ = 0