A can do a work alone in 10 days. B can do the same work alone in 15 days. They start together but B leaves the job 2 days after start and A completes the remaining work alone. What is the total number of days in which the work is completed?

$\frac{26}{3}$

A = 10 days, B = 15 days,

⇒ B worked for 2 days and left = 2 x 2 = 4 units,

⇒ Total work completed by A since day 1 = 30 - 4 = 26 (remaining work)

⇒ \(\frac{26}{3}\) days.

Therefore, time in the which the whole work is completed is \(\frac{26}{3}\) days.