In a right-angled triangle ABC right angled at C, Sin A = Sin B. What is the value of cos A ?

$\frac{\sqrt{3}}{2}$ 1 $\frac{1}{\sqrt{2}}$ $\frac{1}{2}$

$\frac{1}{\sqrt{2}}$

Triangle is right angled at C . So, ∠C = 90º As, sinA = sinB So, ∠A = ∠B ∠A +∠B = 90º ∠A + ∠A = 90º ∠A = 45º Now, cosA =  cos 45º = \(\frac{1}{√2}\)