CUET Preparation Today
CUET
Physics
Nuclei
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t1/2(X) = t(Y)
$\Rightarrow \frac{ln2}{\lambda_X} = \frac{1}{\lambda_Y}$
$\Rightarrow \lambda_X = ln2 \lambda_Y$
$\Rightarrow \lambda_X < \lambda_Y$
Higher is the decay constant, higher is the rate of decay.Y decays at the faster rate.
