If $A$ and $B$ are two events and $A \neq \phi, B \neq \phi$, then |
$P(A \mid B) = P(A) \cdot P(B)$ $P(A \mid B) = \frac{P(A \cap B)}{P(B)}$ $P(A \mid B) \cdot P(B \mid A) = 1$ $P(A \mid B) = P(A) \mid P(B)$ |
$P(A \mid B) = \frac{P(A \cap B)}{P(B)}$ |
The correct answer is Option (2) → $P(A \mid B) = \frac{P(A \cap B)}{P(B)}$ ## If $A \neq \phi$ and $B \neq \phi$, then $P(A \mid B) = \frac{P(A \cap B)}{P(B)}$ [by conditional probability] |