Two numbers are in the ratio 2 : 3. If 5 is subtracted from the first number and six is added to the second number, then the ratio becomes 5 : 12. What would the ratio become when eight is added to each number?
Answer & explanation
Correct answer: option 2
2 : 3
5 : 12
________
-5 +6
$\frac{2R-5}{3R+6} = \frac{5}{12}$
Using cross - multiplication method,
24R - 15R = (6 x 5) - (-5 x 12)
9R = 30 + 60
R = 10
Numbers = 20, 30
When 8 is added to these numbers,
New ratio = 28 : 38 = 14 : 19