If the line drawn from the point (-2, -3, -4) meets a plane at right angle at the point (1, -2, 4), then equation of plane is :
Answer & explanation
Correct answer: option 4
The correct answer is Option (1) → $3x + y + 8z -33 = 0$
point on plane $\vec a=\hat i-2\hat j+4\hat k$
$\vec n=(\hat i-2\hat j+4\hat k)-(-2\hat i-3\hat j-4\hat k)$
$\vec n=3\hat i+\hat j+8\hat k$
So equation → $(\vec r-\vec a).\vec n=0$
$⇒\vec r-\vec n=\vec a.\vec n$
$3x+y+8z=3-2+32$
$3x+y+8z-33=0$