Match List-I with List-II List-

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Target Exam

CUET

Subject

Physics

Chapter

Semiconductors and Electronic Devices

Question:

Match List-I with List-II

List-I	List-II
(A) Intrinsic semiconductor	(I) Number of conduction electrons >> number of holes
(B) n-type semiconductor	(II) Number of conduction electrons << number of holes
(C) p-type semiconductor	(III) Net current is zero
(D) p-n junction under equilibrium	(IV) Number of conduction electrons = number of holes

Choose the correct answer from the options given below:

Options:

(A)-(II), (B)-(IV), (C)-(I), (D)-(III)

(A)-(IV), (B)-(II), (C)-(I), (D)-(III)

(A)-(IV), (B)-(I), (C)-(II), (D)-(III)

(A)-(II), (B)-(I), (C)-(IV), (D)-(III)

Correct Answer:

(A)-(IV), (B)-(I), (C)-(II), (D)-(III)

Explanation:

The correct answer is Option (3) → (A)-(IV), (B)-(I), (C)-(II), (D)-(III)

List-I	List-II
(A) Intrinsic semiconductor	(IV) Number of conduction electrons = number of holes
(B) n-type semiconductor	(I) Number of conduction electrons >> number of holes
(C) p-type semiconductor	(II) Number of conduction electrons << number of holes
(D) p-n junction under equilibrium	(III) Net current is zero