The points A(5, -1, 1), B(7, -4, 7), C(1, -6, 10) and D(-1, -3, 4) are vertices of a
Answer & explanation
Correct answer: option 3
It can easily be seen thet AB = BC = CD = DA = 7.
So, ABCD is a rhombus. Also, $\vec{AB}, \vec{BC}≠ 0.$
So, Ab is not perpendicular to BC. Therefore, ABCD is not a square.
But, $\vec{AC}. \vec{BD}= 0.$
Hence, ABCD is a rhombus.