Read the passage below and answer questions based on it. An electric lamp of resistance 20Ω and a conductor of resistance 4Ω are connected to a 6V battery as shown in the circuit.

Calculate the potential difference across the electric lamp.

4 V 5 V 3 V 2 V

5 V

$I = \frac{V}{r+R} = \frac{6}{24} = 0.25A$ $V = IR = 0.25\times 20 = 5V$