The solution set of the inequation $|2x - 3| ≤ 4$ is |
$\left[\frac{1}{2},\frac{7}{2}\right]$ $\left[-\frac{1}{2},\frac{7}{2}\right]$ $\left[-\frac{1}{2},\frac{5}{2}\right]$ $\left[-\frac{7}{2},\frac{7}{2}\right]$ |
$\left[-\frac{1}{2},\frac{7}{2}\right]$ |
The correct answer is Option (2) → $\left[-\frac{1}{2},\frac{7}{2}\right]$ ** Given inequation: $|2x - 3| \le 4$ Remove absolute value: $-4 \le 2x - 3 \le 4$ Add 3 to all sides: $-1 \le 2x \le 7$ Divide by 2: $-\frac{1}{2} \le x \le \frac{7}{2}$ The solution set is $x \in \left[-\frac{1}{2},\;\frac{7}{2}\right]$. |