Target Exam

CUET

Subject

-- Applied Mathematics - Section B2

Chapter

Numbers, Quantification and Numerical Applications

Question:

The solution set of the inequation $|2x - 3| ≤ 4$ is

Options:

$\left[\frac{1}{2},\frac{7}{2}\right]$

$\left[-\frac{1}{2},\frac{7}{2}\right]$

$\left[-\frac{1}{2},\frac{5}{2}\right]$

$\left[-\frac{7}{2},\frac{7}{2}\right]$

Correct Answer:

$\left[-\frac{1}{2},\frac{7}{2}\right]$

Explanation:

The correct answer is Option (2) → $\left[-\frac{1}{2},\frac{7}{2}\right]$ **

Given inequation:

$|2x - 3| \le 4$

Remove absolute value:

$-4 \le 2x - 3 \le 4$

Add 3 to all sides:

$-1 \le 2x \le 7$

Divide by 2:

$-\frac{1}{2} \le x \le \frac{7}{2}$

The solution set is $x \in \left[-\frac{1}{2},\;\frac{7}{2}\right]$.