A Carnot engine, having an efficiency of h = 1/10 as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is :-

90 J

\(\eta = \frac{1}{\beta + 1}\)

Also, \(\eta = \frac{1}{10}\)

⇒ \(\beta = 9 \)

\(\beta = \frac{Q_2}{W}\)

W = 10

⇒ \(Q_2 = 90 \)