A Carnot engine, having an efficiency of h = 1/10 as heat engine, is used as a refrigerator. If the work done on the system is 10 J, the amount of energy absorbed from the reservoir at lower temperature is :-
Answer & explanation
Correct answer: option 2
\(\eta = \frac{1}{\beta + 1}\)
Also, \(\eta = \frac{1}{10}\)
⇒ \(\beta = 9 \)
\(\beta = \frac{Q_2}{W}\)
W = 10
⇒ \(Q_2 = 90 \)