Practicing Success
If A = \(\begin{bmatrix}5 & 7\\4 & 6 \end{bmatrix}\), then what can be said about 14\( { A }^{ -1 } \)? |
14\( { A }^{ -1 } \) = 7 (adj A) 14\( { A }^{ -1 } \) = -7 (adj A) 14\( { A }^{ -1 } \) = 14 (adj A) 14\( { A }^{ -1 } \) = -14 (adj A) |
14\( { A }^{ -1 } \) = 7 (adj A) |
\( { A }^{ -1 } \) =\(\frac{adj A}{|A|}\) so, |A| = 2 So, \(14 { A }^{ -1 } \) =\(\frac{14×adj A}{2}\) so, \(14{ A }^{ -1 } = 7 (adj A)\) |