The masses of neutron and proton are 1.0087 a.m.u. and 1.0073 a.m.u. respectively. If the neutrons and protons combine to form a helium nucleus (alpha particles) of mass 4.0015 a.m.u. The binding energy of the helium nucleus will be (1 a.m.u.= 931 MeV)
Answer & explanation
Correct answer: option 1
B.E.= $\Delta m c^2=[2(1.0087+1.0073)-4.0015]$ = 28.4 MeV