The ratio of the dimension of Planck's constant and that of the moment of inertia is the dimension of :
Answer & explanation
Correct answer: option 4
\(\frac{h}{I} = \frac{J s}{kg m^2}\)
\(\frac{h}{I} = \frac{ML^2T^{-1}}{ML^2} = \frac{1}{T} ≡ frequency\)