Practicing Success
What is the density (in g L–1) of CO2 at 400 K and exerting a pressure of 0.0821 atm? (R = 0.0821 L atm mol–1 K–1) |
0.01 0.11 2.5 44 |
0.11 |
The correct answer is option 2. 0.11 To find the density (\(d\)) of \(CO_2\) at 400 K and exerting a pressure of 0.0821 atm, we can use the ideal gas law equation: \(PV = nRT\) By rearranging the equation, we can solve for density (\(d\)): \(d = \frac{\text{molar mass} \times P}{R \times T}\) Given: Substituting the values into the equation, we get: \(d = \frac{44 \, \text{g/mol} \times 0.0821 \, \text{atm}}{0.0821 \, \text{L atm mol}^{-1} \text{ K}^{-1} \times 400 \, \text{K}}\) Simplifying the equation, we find: \(d \approx 0.1105 \, \text{g/L}\) Therefore, the density of \(CO_2\) at 400 K and 0.0821 atm is approximately 0.1105 g/L. The correct answer is (2) 0.11. |