Target Exam

CUET

Subject

-- Mathematics - Section B1

Chapter

Applications of Derivatives

Question:

Match List-I with List-II

List-I

List-II

(A) The minimum value of $f(x) = (2x-1)^2+3$

(I) 4

(B) The maximum value of $f(x) = -|x+1|+4$

(II) 10

(C) The minimum value of $f(x) = \sin(2x) + 6$

(III) 3

(D) The maximum value of $f(x) = -(x-1)^2+10$

(IV) 5

Choose the correct answer from the options given below:

Options:

(A)-(I), (B)-(II), (C)-(III), (D)-(IV)

(A)-(III), (B)-(II), (C)-(I), (D)-(IV)

(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

(A)-(III), (B)-(IV), (C)-(I), (D)-(II)

Correct Answer:

(A)-(III), (B)-(I), (C)-(IV), (D)-(II)

Explanation:

The correct answer is Option (3) → (A)-(III), (B)-(I), (C)-(IV), (D)-(II)

List-I

List-II

(A) The minimum value of $f(x) = (2x-1)^2+3$

(III) 3

(B) The maximum value of $f(x) = -|x+1|+4$

(I) 4

(C) The minimum value of $f(x) = \sin(2x) + 6$

(IV) 5

(D) The maximum value of $f(x) = -(x-1)^2+10$

(II) 10

(A) $f(x)=(2x-1)^2+3$

Minimum value occurs when $(2x-1)^2=0$

Minimum $=3$ → (III)

(B) $f(x)=-|x+1|+4$

Maximum value occurs when $|x+1|=0$

Maximum $=4$ → (I)

(C) $f(x)=\sin(2x)+6$

Minimum occurs when $\sin(2x)=-1$

Minimum $=5$ → (IV)

(D) $f(x)=-(x-1)^2+10$

Maximum occurs when $(x-1)^2=0$

Maximum $=10$ → (II)

Correct matching: A–III, B–I, C–IV, D–II.