If the function $f(x)=x^2$ is one-to-one and onto, then the domain D and range R of f(x) are respectively: |
D=[-1, 1], R = set of all real numbers D = set of all real numbers, R = $[0, \infty)$ D = $[0, \infty)$, R = set of all real numbers D = $[0, \infty)$, R = $[0, \infty)$ |
D = $[0, \infty)$, R = $[0, \infty)$ |
The correct answer is Option (4) → D = $[0, \infty)$, R = $[0, \infty)$ $f(x)=x^2$ is one-one ⇒ domain must be [0, ∞) as negative numbers would nullify one-one property for $x∈[0, ∞)$ $f(x)∈[0, ∞)$ = Range |