For $x ∈R$, if $f(x)=-(x-1)^2+2$, then (A) $f$ is an increasing function on $(-∞,1]$ Choose the correct answer from the options given below: |
(B) and (D) only (B), (C) and (D) only (A) and (C) only (A) and (B) only |
(A) and (C) only |
The correct answer is Option (3) → (A) and (C) only Given: $f(x) = - (x - 1)^2 + 2$ First derivative: $f'(x) = -2(x - 1)$ Set $f'(x) = 0$ ⟹ $x = 1$ is a critical point. Sign of $f'(x)$: • For $x < 1$: $f'(x) > 0$ ⟹ function increasing • For $x > 1$: $f'(x) < 0$ ⟹ function decreasing ⟹ First derivative test confirms a maximum at $x = 1$. Second derivative: $f''(x) = -2$ (always negative) ⟹ Second derivative test confirms maximum at $x = 1$ |