Practicing Success

Target Exam

CUET

Subject

Physics

Chapter

Electromagnetic Induction

Question:

Options:

a

b

c

d

Correct Answer:

a

Explanation:

$\Xi_{max} = BA\omega = 0.01\times \pi \times 1^2 \times 2\pi \times 100 = 2\pi^2$

$ E_{max}.2\pi r = \xi_{max} = 2\pi^2$

$ E_{max} = \pi V/m$