The probability distribution of a random

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Target Exam

CUET

Subject

-- Mathematics - Section B2

Chapter

Probability Distributions

Question:

The probability distribution of a random variable X is given as under :

$P(X=x)=\left\{\begin{array}{cc}
K x^2 & \text { for } x=1,2,3 \\
2 K x & \text { for } x=4,5,6 \\
0 & \text { otherwise, }
\end{array}\right.$

where K is a constant. Then P(x < 4) is equal to:

Options:

$\frac{3}{22}$

$\frac{7}{22}$

$\frac{15}{22}$

$\frac{17}{22}$

Correct Answer:

$\frac{7}{22}$

Explanation:

The correct answer is Option (2) → $\frac{7}{22}$