$\int\frac{dx}{\sqrt{2x-x^2}}$ is equal to
Answer & explanation
Correct answer: option 3
Let $I=\int\frac{dx}{\sqrt{1-(x^2-2x+1)}}=\int\frac{dx}{\sqrt{1-(x-1)^2}}=sin^{-1}(\frac{x-1}{1})+c$.
Hence (C) is the correct answer.
$\int\frac{dx}{\sqrt{2x-x^2}}$ is equal to
Correct answer: option 3
Let $I=\int\frac{dx}{\sqrt{1-(x^2-2x+1)}}=\int\frac{dx}{\sqrt{1-(x-1)^2}}=sin^{-1}(\frac{x-1}{1})+c$.
Hence (C) is the correct answer.