If mean of Binomial distribution is 6 and variance is 2. Then the value of p, where p denotes probability of success is :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) → $\frac{2}{3}$
Mean $μ=np=6$
Variance $(σ^2)=npq=2$
So $\frac{σ^2}{μ}=\frac{npq}{np}=\frac{2}{6}⇒q=\frac{1}{3}⇒p=\frac{2}{3}$