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If mean of Binomial distribution is 6 and variance is 2. Then the value of p, where p denotes probability of success is : |
$\frac{2}{3}$ $\frac{2}{5}$ $\frac{3}{5}$ $\frac{1}{5}$ |
$\frac{2}{3}$ |
The correct answer is Option (1) → $\frac{2}{3}$ Mean $μ=np=6$ Variance $(σ^2)=npq=2$ So $\frac{σ^2}{μ}=\frac{npq}{np}=\frac{2}{6}⇒q=\frac{1}{3}⇒p=\frac{2}{3}$ |
