Let $A=\left[\begin{array}{cc}3 & -1 \\ 2 & 4\end{array}\right]$, then adjoint (A) is: |
$\left[\begin{array}{cc}3 & 2 \\ -1 & 4\end{array}\right]$ $\left[\begin{array}{cc}4 & -1 \\ 2 & 3\end{array}\right]$ $\left[\begin{array}{cc}-4 & 1 \\ -2 & -3\end{array}\right]$ $\left[\begin{array}{cc}4 & 1 \\ -2 & 3\end{array}\right]$ |
$\left[\begin{array}{cc}4 & 1 \\ -2 & 3\end{array}\right]$ |
$A=\left[\begin{array}{cc}3 & -1 \\ 2 & 4\end{array}\right]$ here finding cofactors so C11 = 4 C12 = -2 C21 = 1 C22 = 3 so Adj A = $\left[\begin{array}{ll}c_{11} & c_{12} \\ c_{21} & c_{22}\end{array}\right]^{T}=\left[\begin{array}{cc}4 & -2 \\ 1 & 3\end{array}\right]^{T}$ $=\left[\begin{array}{cc}4 & 1 \\ -2 & 3\end{array}\right]$ |