Practicing Success

Target Exam

CUET

Subject

-- Mathematics - Section A

Chapter

Determinants

Question:

Let $A=\left[\begin{array}{cc}3 & -1 \\ 2 & 4\end{array}\right]$, then adjoint (A) is:

Options:

$\left[\begin{array}{cc}3 & 2 \\ -1 & 4\end{array}\right]$

$\left[\begin{array}{cc}4 & -1 \\ 2 & 3\end{array}\right]$

$\left[\begin{array}{cc}-4 & 1 \\ -2 & -3\end{array}\right]$

$\left[\begin{array}{cc}4 & 1 \\ -2 & 3\end{array}\right]$

Correct Answer:

$\left[\begin{array}{cc}4 & 1 \\ -2 & 3\end{array}\right]$

Explanation:

$A=\left[\begin{array}{cc}3 & -1 \\ 2 & 4\end{array}\right]$

here finding cofactors

so C11 = 4     C12 = -2

C21 = 1     C22 = 3

so  Adj A = $\left[\begin{array}{ll}c_{11} & c_{12} \\ c_{21} & c_{22}\end{array}\right]^{T}=\left[\begin{array}{cc}4 & -2 \\ 1 & 3\end{array}\right]^{T}$

$=\left[\begin{array}{cc}4 & 1 \\ -2 & 3\end{array}\right]$