The value of the integral ∫ e^x≤ft(1/x-1/(x^2)) d x is :

$I = \int e^x\left(\frac{1}{x}-\frac{1}{x^2}\right) d x$

this of the type

$\int e^x (f(x) + f'(x)) dx = e^x f(x) + C$

here $f(x) = \frac{1}{x}~~~~~~f'(x) = \frac{1}{x^2}$

$I = \frac{e^x}{x}+C$