Target Exam

CUET

Subject

Physics

Chapter

Gravitation

Question:

The smallest and greatest distances a planet travels around the sun are r and R, respectively. If the planet’s minimum speed on its journey is v0, its maximum speed is :

Options:

\(\frac{v_o R }{r}\)

\(\frac{v_o r }{R}\)

\(\frac{v_o R^2 }{r^2}\)

\(\frac{v_o r^2 }{R^2}\)

Correct Answer:

\(\frac{v_o R }{r}\)

Explanation:

By Kepler's law, the areal velocity = \(\frac{L}{2m}\)​ is a constant and hence L (angular momentum) is constant.

mvr = constant (at any point of trajectory)

Minimum speed (v0​) is possible at the maximum distance (R) from sun and maximum speed (v′) is possible at the minimum distance (r) from the sun.

mvoR=mvr  

\(v' = \frac{v_o R}{r}\)