Answer the question on the basis of passage given below: |
For the preparation of phenylethanoic acid from benzyl alcohol, reagents required are A. \(HBr\) B. \(CO_2\) C. \(KCN\) D. \(\Delta / H_3O^+\) E. \(AgNO_3\) Choose the correct answer from the options given below: |
A, B and C only A, C and D only A, C and E only A, B and E only |
A, C and D only |
The correct answer is option 2. A, C and D only. Let us break down the process of converting benzyl alcohol to phenylethanoic acid and understand why the specific reagents are required: Step 1: Conversion of Benzyl Alcohol to Benzyl Bromide
Benzyl alcohol \((C_6H_5CH_2OH)\) is treated with hydrobromic acid \((HBr)\) to convert the hydroxyl group \((-OH)\) into a bromide group, forming benzyl bromide \((C_6H_5CH_2Br)\). This is a typical substitution reaction where the -OH group is replaced by a -Br atom. Step 2: Conversion of Benzyl Bromide to Phenylacetonitrile
Benzyl bromide is then reacted with potassium cyanide \((KCN)\), which introduces a cyanide group \((-CN)\) in place of the bromide, forming phenylacetonitrile \((C_6H_5CH_2CN)\). This is a nucleophilic substitution reaction where the cyanide ion replaces the bromide ion. Step 3: Hydrolysis of Phenylacetonitrile to Phenylethanoic Acid
Phenylacetonitrile is hydrolyzed under acidic conditions with heat to convert the nitrile group \((-CN)\) into a carboxylic acid group \((-COOH)\), resulting in phenylethanoic acid \((C_6H_5CH_2COOH)\). This is a two-step hydrolysis process where the nitrile first converts to an amide \((-CONH_2)\), and then to the carboxylic acid \((-COOH)\). Therefore, the correct sequence of reagents for the synthesis of phenylethanoic acid from benzyl alcohol includes A (HBr), C (KCN), and D (Δ / H_3O^+). The correct option is: 2. A, C, and D only. |