A parallel plate capacitor consists of two circular plates each of radius 12 cm and separated by 5.0 mm. The capacitor is being charged by an external source. The charging is being charged and is equal to 0.15 A. The rate of change of potential difference between the plates will be:

1.873 x 10⁹ V/s 

$ \frac{dV}{dt} = \frac{I_d}{C} = \frac{I_d d}{\epsilon_0 A} = \frac{0.15\times 5\times 10^{-3}}{8.85\times 10^{-12}\times 3.14\times0.0144} = 1.873\times 10^9V/s$