CUET Preparation Today
CUET
General Test
Quantitative Reasoning
Trigonometry
What will be the value of \(\frac{sin\;19°}{cos\;71°}\) ?
2
-1
1
0
\(\frac{sin\;19°}{cos\;71°}\) = \(\frac{sin\;(90°-71°)}{cos\;71°}\)
= \(\frac{cos\;71°}{cos\;71°}\)
= 1
