The average of 19 numbers is 48. The average of the first 7 numbers is 50.6 and that of the last 13 numbers is 47.6. If the number is excluded, then what is the average of the remaining numbers (correct to one decimal place)?

47.3

Sum of 19 numbers is = 19 × 48 = 912

Sum of first 7 numbers is = 7 × 50.6 = 354.2

Sum  of last 13 numbers = 13 × 47.6 = 618.8

7th number = ( 354.2 + 618.8) - 912 = 61

Average of remaining numbers = \(\frac{912 - 61 }{18}\) 

= \(\frac{851 }{18}\)  = 47.27

= 47.3  ( approx )