CUET Preparation Today
A die is rolled thrice. What is the probability of getting a number greater than 4 in the first and the second throw of dice and a number less than 4 in the third throw? |
$\frac{1}{3}$ $\frac{1}{6}$ $\frac{1}{9}$ $\frac{1}{18}$ |
$\frac{1}{18}$ |
The correct answer is Option (4) - $\frac{1}{18}$ Probability = P(num > 4) × P(num > 4) × P(num > 4) $=\frac{2}{6}×\frac{2}{6}×\frac{3}{6}=\frac{1}{18}$ |
