The probability distribution of number of heads in two tosses of a coin is :
Answer & explanation
Correct answer: option 1
The correct answer is Option (1) →
| $x_i$ | 0 | 1 | 2 |
| $P_i$ | 1/4 | 1/2 | 1/4 |
X → no of heads in two tosses
$P(X=0)={^2C}_0(\frac{1}{2})^0(\frac{1}{2})^2=\frac{1}{4}$
$P(X=1)={^2C}_1(\frac{1}{2})(\frac{1}{2})=\frac{1}{2}$
$P(X=2)={^2C}_2(\frac{1}{2})(\frac{1}{2})=\frac{1}{4}$