For a cost-minimisation problem, the corner points of the bounded feasible region are (2, 0), (5, 0), (5, 4), (0, 6) and (0, 3). If the cost is Z = 30x + 25y (in Rs.), then the minimum cost is
Answer & explanation
Correct answer: option 4
The correct answer is Option (4) → Rs. 60
On a bounded feasible region the minimum of Z occurs at a corner point. Values of Z:
\(Z(2, 0) = 60\)
\(Z(5, 0) = 150\)
\(Z(5, 4) = 150 + 100 = 250\)
\(Z(0, 6) = 150\)
\(Z(0, 3) = 75\)
The smallest value is 60, so the minimum cost is Rs. 60 (at x = 2, y = 0).