Practicing Success
The maximum value of z = 4x + 3y subject to constraint x + y ≤ 6, x, y ≥ 0 is : |
18 24 40 34 |
24 |
z = 4x + 3y → function constrains x + y ≤ 6 x, y ≥ 0 (in first quadrant) plotting first for x + y = 6
Now checking for (0, 0) point for inequality x + y ≤ 6 0 ≤ 6 ⇒ Solution lies to side of equation x + y =6 containing (0, 0) Corner points obtained (0, 0) (0, 6) (6, 0) function z = 4x + 3y z(x, y) = 4x + 3y So z(0, 0) = 0 + 0 = 0 z(0, 6) = 18 z(6, 0) = 24 Max value is at point (6, 0) which is 24 |