Practicing Success
Practicing Success
CUET Preparation Today
$\int \frac{\sec x ~cosec ~x}{\log \tan x} d x$ |
log (tan x) cot (log x) log log (tan x) tan (log x) |
log log (tan x) |
put log tan x = t $\frac{1}{\tan x} \sec ^2 x d x=d t$ sec x cosec x dx = dt $\int \frac{dt}{t}$ = log t + c = log (log tan x) Hence (3) is the correct answer. |
