A is thrice as good a workman as B and together they can finish a work in 32 days. In how many days will B alone complete the same work?

128 days

As Given,

A is thrice as good a workman as B, therefore,

⇒ A : B = 3: 1 (Efficiency)

⇒ A + B can finish a work in 32 days = (3 + 1) x 32 = 128 units  ..(Efficiency × Days = Total work)

⇒ B alone complete the same work in = \(\frac{128}{1}\) = 128 days  ..(\(\frac{Work}{Efficiency}\) = Time ).

Therefore, B can complete the total work alone in 128 days.